98=2w^2+8

Solution for 98=2w^2+8 equation:

98=2w^2+8

We move all terms to the left:

98-(2w^2+8)=0

We get rid of parentheses

-2w^2-8+98=0

We add all the numbers together, and all the variables

-2w^2+90=0

a = -2; b = 0; c = +90;
Δ = b2-4ac
Δ = 02-4·(-2)·90
Δ = 720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{720}=\sqrt{144*5}=\sqrt{144}*\sqrt{5}=12\sqrt{5}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{5}}{2*-2}=\frac{0-12\sqrt{5}}{-4}
=-\frac{12\sqrt{5}}{-4}
=-\frac{3\sqrt{5}}{-1}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{5}}{2*-2}=\frac{0+12\sqrt{5}}{-4}
=\frac{12\sqrt{5}}{-4}
=\frac{3\sqrt{5}}{-1}
$